Alexander, North Dakota

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Alexander is a city in McKenzie County, North Dakota in the United States. The population was 217 at the 2000 census. Alexander was founded in 1905 and is named after early North Dakota politician Alexander McKenzie.

Contents

Geography

Alexander is located at 47°50′33″N 103°38′34″W / 47.8425°N 103.64278°W / 47.8425; -103.64278 (47.842501, -103.642839).[3]

According to the United States Census Bureau, the city has a total area of 1.4 square miles (3.7 km²), all of it land.

Demographics

As of the census[1] of 2000, there were 217 people, 87 households, and 60 families residing in the city. The population density was 150.6 people per square mile (58.2/km²). There were 106 housing units at an average density of 73.6/sq mi (28.4/km²). The racial makeup of the city was 93.55% White, 5.99% Native American, 0.46% from other races. Hispanic or Latino of any race were 1.38% of the population.

The top 6 ancestry groups in the city are Norwegian (49.3%), German (32.7%), Irish (18.0%), English (8.3%), Swedish (7.4%), Dutch (4.1%).

There were 87 households out of which 32.2% had children under the age of 18 living with them, 59.8% were married couples living together, 4.6% had a female householder with no husband present, and 31.0% were non-families. 28.7% of all households were made up of individuals and 10.3% had someone living alone who was 65 years of age or older. The average household size was 2.49 and the average family size was 3.08.

In the city the population was spread out with 27.6% under the age of 18, 5.1% from 18 to 24, 19.8% from 25 to 44, 30.4% from 45 to 64, and 17.1% who were 65 years of age or older. The median age was 43 years. For every 100 females there were 93.8 males. For every 100 females age 18 and over, there were 103.9 males.

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