Allen, South Dakota

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Allen is a census-designated place in Bennett County, South Dakota. As of the 2000 census, the CDP had a population of 419. It is considered the poorest place in the United States.



Allen is located at 43°16′50″N 101°55′40″W / 43.28056°N 101.92778°W / 43.28056; -101.92778 (43.280547, -101.927689)[1].

According to the United States Census Bureau, the CDP has a total area of 3.9 square miles (10.2 km²), all of it land.

Allen has been assigned the ZIP code 57714.


As of the census[2] of 2000, there were 419 people, 80 households, and 70 families residing in the CDP. The population density was 106.8 people per square mile (41.3/km²). There were 87 housing units at an average density of 22.2/sq mi (8.6/km²).

There were 80 households out of which 62.5% had children under the age of 18 living with them, 21.3% were married couples living together, 50.0% had a female householder with no husband present, and 12.5% were non-families. 10.0% of all households were made up of individuals and 1.3% had someone living alone who was 65 years of age or older. The average household size was 5.24 and the average family size was 5.51.

In the CDP the population was spread out with 50.4% under the age of 18, 13.8% from 18 to 24, 21.5% from 25 to 44, 12.2% from 45 to 64, and 2.1% who were 65 years of age or older. The median age was 18 years. For every 100 females there were 99.5 males. For every 100 females age 18 and over, there were 89.1 males.

Race and ethnicity

The racial makeup of the CDP was 4.30% White, 94.03% Native American, and 1.67% from two or more races. Hispanic or Latino of any race were 1.43% of the population.


The median income for a household in the CDP was $7,578, and the median income for a family was $3,819. Males had a median income of $0 versus $12,188 for females. The per capita income for the CDP was $1,539. About 95.9% of families and 96.1% of the population were below the poverty line, including 97.1% of those under age 18 and 100.0% of those age 65 or over.

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