Arthur, Iowa

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Arthur is a city in Ida County, Iowa, United States. The population was 245 at the 2000 census.


Arthur is located at 42°20′7″N 95°20′48″W / 42.33528°N 95.34667°W / 42.33528; -95.34667 (42.335225, -95.346658)[1].

According to the United States Census Bureau, the city has a total area of 0.2 square miles (0.4 km²), all of it land.


As of the census[2] of 2000, there were 245 people, 112 households, and 62 families residing in the city. The population density was 1,600.1 people per square mile (630.6/km²). There were 117 housing units at an average density of 764.1/sq mi (301.2/km²). The racial makeup of the city was 100.00% White.

There were 112 households out of which 27.7% had children under the age of 18 living with them, 49.1% were married couples living together, 3.6% had a female householder with no husband present, and 44.6% were non-families. 42.9% of all households were made up of individuals and 29.5% had someone living alone who was 65 years of age or older. The average household size was 2.19 and the average family size was 3.08.

In the city the population was spread out with 26.5% under the age of 18, 7.3% from 18 to 24, 24.5% from 25 to 44, 17.6% from 45 to 64, and 24.1% who were 65 years of age or older. The median age was 41 years. For every 100 females there were 81.5 males. For every 100 females age 18 and over, there were 81.8 males.

The median income for a household in the city was $25,833, and the median income for a family was $36,250. Males had a median income of $28,750 versus $17,500 for females. The per capita income for the city was $14,007. About 4.7% of families and 8.0% of the population were below the poverty line, including 6.7% of those under the age of eighteen and 10.2% of those sixty five or over.


Arthur | Battle Creek | Galva | Holstein | Ida Grove

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