Bernice, Oklahoma

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Bernice is a town in Delaware County, Oklahoma, United States. The population was 504 at the 2000 census.



Bernice is located at 36°37′31″N 94°54′49″W / 36.62528°N 94.91361°W / 36.62528; -94.91361 (36.625286, -94.913643)[3].

According to the United States Census Bureau, the town has a total area of 1.5 square miles (3.8 km²), of which, 0.9 square miles (2.3 km²) of it is land and 0.6 square miles (1.5 km²) of it (38.62%) is water.


As of the census[1] of 2000, there were 504 people, 245 households, and 152 families residing in the town. The population density was 565.0 people per square mile (218.6/km²). There were 385 housing units at an average density of 431.6/sq mi (167.0/km²). The racial makeup of the town was 81.35% White, 12.90% Native American, and 5.75% from two or more races. Hispanic or Latino of any race were 1.19% of the population.

There were 245 households out of which 20.0% had children under the age of 18 living with them, 55.5% were married couples living together, 3.3% had a female householder with no husband present, and 37.6% were non-families. 35.5% of all households were made up of individuals and 15.5% had someone living alone who was 65 years of age or older. The average household size was 2.06 and the average family size was 2.59.

In the town the population was spread out with 16.7% under the age of 18, 6.3% from 18 to 24, 20.8% from 25 to 44, 31.3% from 45 to 64, and 24.8% who were 65 years of age or older. The median age was 51 years. For every 100 females there were 104.9 males. For every 100 females age 18 and over, there were 102.9 males.

The median income for a household in the town was $24,844, and the median income for a family was $30,288. Males had a median income of $24,444 versus $15,833 for females. The per capita income for the town was $15,005. About 9.5% of families and 14.1% of the population were below the poverty line, including 24.4% of those under age 18 and 13.2% of those age 65 or over.


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