Bishopville, South Carolina

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Bishopville is a city in Lee County, South Carolina, United States. The population was 3,670 at the 2000 census. It is the county seat of Lee County[3].

Contents

Geography

Bishopville is located at 34°13′8″N 80°14′56″W / 34.21889°N 80.24889°W / 34.21889; -80.24889 (34.219027, -80.248877)[4].

According to the United States Census Bureau, the city has a total area of 2.4 square miles (6.2 km²), of which, 2.4 square miles (6.1 km²) of it is land and 0.04 square miles (0.1 km²) of it (1.26%) is water.

Demographics

As of the census[1] of 2000, there were 3,670 people, 1,438 households, and 907 families residing in the city. The population density was 1,554.8 people per square mile (600.4/km²). There were 1,616 housing units at an average density of 684.6/sq mi (264.4/km²). The racial makeup of the city was 65.83% African American, 32.83% White, 0.11% Native American, 0.44% Asian, 0.22% from other races, and 0.57% from two or more races. Hispanic or Latino of any race were 1.31% of the population.

There were 1,438 households out of which 31.6% had children under the age of 18 living with them, 29.8% were married couples living together, 29.6% had a female householder with no husband present, and 36.9% were non-families. 34.2% of all households were made up of individuals and 16.1% had someone living alone who was 65 years of age or older. The average household size was 2.43 and the average family size was 3.12.

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