Bondurant, Iowa

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Bondurant is a city in Polk County, Iowa, United States. The population was 1,846 at the 2000 census; a special census taken in 2006 counted 2,951 residents.[1] It is part of the Des MoinesWest Des Moines Metropolitan Statistical Area.



Bondurant was founded in 1884. Bondurant incorporated as a city on December 23, 1897. It was named for Alexander C. Bondurant, who was the area's first settler in 1857.[2]


Bondurant is located at 41°41′39″N 93°27′41″W / 41.694304°N 93.461488°W / 41.694304; -93.461488 (41.694304, -93.461488).[3]

According to the United States Census Bureau, the city has a total area of 4.8 square miles (12.5 km2), of which, 4.8 square miles (12.4 km2) of it is land and 0.04 square miles (0.1 km2) of it (0.42%) is water.


As of the census[4] of 2000, there were 1,846 people, 659 households, and 508 families residing in the city. The population density was 385.9 people per square mile (149.1/km2). There were 682 housing units at an average density of 142.6/sq mi (55.1/km2). The racial makeup of the city was 98.43% White, 0.22% Native American, 0.16% Asian, 0.33% from other races, and 0.87% from two or more races. Hispanic or Latino of any race were 0.87% of the population.

There were 659 households out of which 46.9% had children under the age of 18 living with them, 61.9% were married couples living together, 12.1% had a female householder with no husband present, and 22.9% were non-families. 19.9% of all households were made up of individuals and 6.5% had someone living alone who was 65 years of age or older. The average household size was 2.80 and the average family size was 3.24.

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