Bowersville, Georgia

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Bowersville is a town in Hart County, Georgia, United States. The population was 334 at the 2000 census.


Bowersville is located at 34°22′19″N 83°4′57″W / 34.37194°N 83.0825°W / 34.37194; -83.0825 (34.371995, -83.082392)[3].

According to the United States Census Bureau, the town has a total area of 3.1 square miles (8.0 km²), of which, 3.1 square miles (8.0 km²) of it is land and 0.32% is water.


As of the census[1] of 2000, there were 334 people, 136 households, and 99 families residing in the town. The population density was 108.1 people per square mile (41.7/km²). There were 156 housing units at an average density of 50.5/sq mi (19.5/km²). The racial makeup of the town was 85.33% White, 12.87% African American, 0.30% Native American, and 1.50% from two or more races.

There were 136 households out of which 31.6% had children under the age of 18 living with them, 52.9% were married couples living together, 16.2% had a female householder with no husband present, and 26.5% were non-families. 25.7% of all households were made up of individuals and 11.0% had someone living alone who was 65 years of age or older. The average household size was 2.46 and the average family size was 2.92.

In the town the population was spread out with 25.7% under the age of 18, 6.9% from 18 to 24, 29.9% from 25 to 44, 24.3% from 45 to 64, and 13.2% who were 65 years of age or older. The median age was 34 years. For every 100 females there were 84.5 males. For every 100 females age 18 and over, there were 83.7 males.

The median income for a household in the town was $30,625, and the median income for a family was $36,944. Males had a median income of $26,607 versus $19,583 for females. The per capita income for the town was $13,645. About 15.7% of families and 17.6% of the population were below the poverty line, including 14.7% of those under age 18 and 25.0% of those age 65 or over.


Canon‡ | Hartwell | Royston


Reed Creek

‡This populated place also has portions in an adjacent county or counties

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