Brayton, Iowa

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Brayton is a city in Audubon County, Iowa, United States, along the East Nishnabotna River. The population was 145 at the 2000 census.



In recent decades, Brayton's population has fallen; its 1950 population was 239.[citation needed]


Brayton is located at 41°32′43″N 94°55′33″W / 41.54528°N 94.92583°W / 41.54528; -94.92583 (41.545283, -94.925865)[1].

According to the United States Census Bureau, the city has a total area of 0.6 square miles (1.6 km²), all of it land.


As of the census[2] of 2000, there were 145 people, 67 households, and 43 families residing in the city. The population density was 235.4 people per square mile (90.3/km²). There were 73 housing units at an average density of 118.5/sq mi (45.5/km²). The racial makeup of the city was 99.31% White and 0.69% Native American.

There were 67 households out of which 20.9% had children under the age of 18 living with them, 56.7% were married couples living together, 6.0% had a female householder with no husband present, and 35.8% were non-families. 29.9% of all households were made up of individuals and 19.4% had someone living alone who was 65 years of age or older. The average household size was 2.16 and the average family size was 2.65.

In the city the population was spread out with 19.3% under the age of 18, 8.3% from 18 to 24, 20.7% from 25 to 44, 17.9% from 45 to 64, and 33.8% who were 65 years of age or older. The median age was 46 years. For every 100 females there were 101.4 males. For every 100 females age 18 and over, there were 95.0 males.

The median income for a household in the city was $25,875, and the median income for a family was $25,625. Males had a median income of $30,833 versus $15,833 for females. The per capita income for the city was $12,166. There were none of the families and 3.9% of the population living below the poverty line, including no under eighteens and 1.8% of those over 64.

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