Bryant, Illinois

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{household, population, female}
{village, small, smallsup}

Bryant is a village in Fulton County, Illinois, United States. The population was 255 at the 2000 census.



Bryant is located at 40°28′1″N 90°5′43″W / 40.46694°N 90.09528°W / 40.46694; -90.09528 (40.466839, -90.095388).[1]

According to the United States Census Bureau, the village has a total area of 0.3 square miles (0.7 km²), all of it land.


As of the census[2] of 2000, there were 255 people, 96 households, and 72 families residing in the village. The population density was 994.6 people per square mile (378.7/km²). There were 104 housing units at an average density of 405.7/sq mi (154.4/km²). The racial makeup of the village was 97.65% White, 0.78% African American, 0.39% Asian, 1.18% from other races. Hispanic or Latino of any race were 1.57% of the population.

There were 96 households out of which 32.3% had children under the age of 18 living with them, 59.4% were married couples living together, 10.4% had a female householder with no husband present, and 24.0% were non-families. 15.6% of all households were made up of individuals and 10.4% had someone living alone who was 65 years of age or older. The average household size was 2.66 and the average family size was 2.97.

In the village the population was spread out with 24.3% under the age of 18, 13.3% from 18 to 24, 27.8% from 25 to 44, 18.4% from 45 to 64, and 16.1% who were 65 years of age or older. The median age was 34 years. For every 100 females there were 94.7 males. For every 100 females age 18 and over, there were 96.9 males.

The median income for a household in the village was $28,636, and the median income for a family was $28,977. Males had a median income of $31,875 versus $23,571 for females. The per capita income for the village was $13,740. About 10.1% of families and 14.3% of the population were below the poverty line, including 31.6% of those under the age of eighteen and none of those sixty five or over.


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