Burlington, Wyoming

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Burlington is a town in Big Horn County, Wyoming, United States. The population was 250 at the 2000 census.



Burlington is located at 44°26′46″N 108°25′50″W / 44.44611°N 108.43056°W / 44.44611; -108.43056 (44.446053, -108.430579)[3].

According to the United States Census Bureau, the town has a total area of 1.0 square miles (2.6 km²), all of it land.


As of the census[1] of 2000, there were 250 people, 76 households, and 58 families residing in the town. The population density was 246.6 people per square mile (95.6/km²). There were 87 housing units at an average density of 85.8/sq mi (33.3/km²). The racial makeup of the town was 88.80% White, 0.80% Native American, 1.20% Pacific Islander, 8.80% from other races, and 0.40% from two or more races. Hispanic or Latino of any race were 10.00% of the population.

There were 76 households out of which 46.1% had children under the age of 18 living with them, 71.1% were married couples living together, 5.3% had a female householder with no husband present, and 22.4% were non-families. 21.1% of all households were made up of individuals and 10.5% had someone living alone who was 65 years of age or older. The average household size was 3.29 and the average family size was 3.90.

In the town the population was spread out with 44.4% under the age of 18, 2.8% from 18 to 24, 24.8% from 25 to 44, 13.2% from 45 to 64, and 14.8% who were 65 years of age or older. The median age was 29 years. For every 100 females there were 101.6 males. For every 100 females age 18 and over, there were 98.6 males.

The median income for a household in the town was $28,281, and the median income for a family was $31,875. Males had a median income of $29,375 versus $15,625 for females. The per capita income for the town was $13,129. About 7.7% of families and 15.1% of the population were below the poverty line, including 19.5% of those under the age of eighteen and 2.4% of those sixty five or over.

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