Butler, Indiana

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Butler is a city in DeKalb County, Indiana, United States. The population was 2,725 at the 2000 census.



Butler is located at 41°25′49″N 84°52′19″W / 41.430166°N 84.871859°W / 41.430166; -84.871859.[3]

According to the United States Census Bureau, the city has a total area of 1.8 square miles (4.6 km²), all of it land.


As of the census[1] of 2000, there were 2,725 people, 983 households, and 699 families residing in the city. The population density was 1,523.6 people per square mile (587.8/km²). There were 1,075 housing units at an average density of 601.1/sq mi (231.9/km²). The racial makeup of the city was 97.69% White, 0.15% African American, 0.18% Native American, 0.11% Asian, 1.25% from other races, and 0.62% from two or more races. Hispanic or Latino of any race were 2.24% of the population.

There were 983 households out of which 40.5% had children under the age of 18 living with them, 53.8% were married couples living together, 12.1% had a female householder with no husband present, and 28.8% were non-families. 23.6% of all households were made up of individuals and 8.1% had someone living alone who was 65 years of age or older. The average household size was 2.68 and the average family size was 3.17.

In the city the population was spread out with 30.8% under the age of 18, 10.3% from 18 to 24, 30.5% from 25 to 44, 18.3% from 45 to 64, and 10.2% who were 65 years of age or older. The median age was 31 years. For every 100 females there were 94.9 males. For every 100 females age 18 and over, there were 90.2 males.

The median income for a household in the city was $37,250, and the median income for a family was $42,188. Males had a median income of $32,361 versus $21,404 for females. The per capita income for the city was $15,040. About 5.5% of families and 9.7% of the population were below the poverty line, including 11.7% of those under age 18 and 14.1% of those age 65 or over.

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