Butler, Waukesha County, Wisconsin

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Butler is a village in Waukesha County, Wisconsin, United States. The population was 1,881 at the 2000 census.



Butler is located at 43°6′26″N 88°4′8″W / 43.10722°N 88.06889°W / 43.10722; -88.06889 (43.107310, -88.068963).[1]

According to the United States Census Bureau, the village has a total area of 0.8 square miles (2.0 km²), all of it land.


As of the census[2] of 2000, there were 1,881 people, 916 households, and 459 families residing in the village. The population density was 2,376.2 people per square mile (919.3/km²). There were 938 housing units at an average density of 1,184.9/sq mi (458.4/km²). The racial makeup of the village was 97.40% White, 0.27% African American, 1.06% Native American, 0.48% Asian, 0.16% Pacific Islander, and 0.64% from two or more races. Hispanic or Latino of any race were 0.85% of the population.

There were 916 households out of which 20.7% had children under the age of 18 living with them, 39.0% were married couples living together, 8.1% had a female householder with no husband present, and 49.8% were non-families. 42.5% of all households were made up of individuals and 25.3% had someone living alone who was 65 years of age or older. The average household size was 2.05 and the average family size was 2.88.

In the village the population was spread out with 19.5% under the age of 18, 6.2% from 18 to 24, 30.8% from 25 to 44, 20.0% from 45 to 64, and 23.5% who were 65 years of age or older. The median age was 41 years. For every 100 females there were 89.8 males. For every 100 females age 18 and over, there were 86.1 males.

The median income for a household in the village was $38,333, and the median income for a family was $50,903. Males had a median income of $35,781 versus $26,250 for females. The per capita income for the village was $22,167. None of the families and 2.4% of the population were living below the poverty line, including no under eighteens and 7.8% of those over 64.

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