Copan, Oklahoma

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Copan is a town in Washington County, Oklahoma, United States. The population was 796 at the 2000 census.



Copan is located at 36°54′0″N 95°55′35″W / 36.9°N 95.92639°W / 36.9; -95.92639 (36.899926, -95.926447)[3].

According to the United States Census Bureau, the town has a total area of 1.0 square miles (2.6 km²), all of it land.


As of the census[1] of 2000, there were 796 people, 346 households, and 232 families residing in the town. The population density was 777.7 people per square mile (301.3/km²). There were 386 housing units at an average density of 377.1/sq mi (146.1/km²). The racial makeup of the town was 81.53% White, 13.07% Native American, 0.38% Asian, 0.63% from other races, and 4.40% from two or more races. Hispanic or Latino of any race were 1.76% of the population.

There were 346 households out of which 28.0% had children under the age of 18 living with them, 54.9% were married couples living together, 9.5% had a female householder with no husband present, and 32.7% were non-families. 30.9% of all households were made up of individuals and 13.3% had someone living alone who was 65 years of age or older. The average household size was 2.30 and the average family size was 2.88.

In the town the population was spread out with 24.9% under the age of 18, 6.0% from 18 to 24, 24.4% from 25 to 44, 27.0% from 45 to 64, and 17.7% who were 65 years of age or older. The median age was 41 years. For every 100 females there were 93.2 males. For every 100 females age 18 and over, there were 85.1 males.

The median income for a household in the town was $27,222, and the median income for a family was $36,563. Males had a median income of $30,938 versus $20,119 for females. The per capita income for the town was $16,324. About 6.8% of families and 12.1% of the population were below the poverty line, including 14.4% of those under age 18 and 10.4% of those age 65 or over.


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