Cottonwood, South Dakota

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Cottonwood is a town in Jackson County, South Dakota, United States. The population was 6 at the 2000 census.


Cottonwood is located at 43°57′59″N 101°54′20″W / 43.96639°N 101.90556°W / 43.96639; -101.90556 (43.966333, -101.905478)[4].

According to the United States Census Bureau, the town has a total area of 0.9 square miles (2.4 km²), all of it land.


As of the census[2] of 2000, there were 6 people, 4 households, and 2 families residing in the town. The population density was 6.5 people per square mile (2.5/km²). There were 5 housing units at an average density of 5.4/sq mi (2.1/km²). The racial makeup of the town was 100.00% White.

There were 4 households out of which none had children under the age of 18 living with them, 50.0% were married couples living together, and 50.0% were non-families. 50.0% of all households were made up of individuals and 50.0% had someone living alone who was 65 years of age or older. The average household size was 1.50 and the average family size was 2.00.

In the town the population was spread out with 33.3% from 45 to 64, and 66.7% who were 65 years of age or older. The median age was 66 years. For every 100 females there were 100.0 males. For every 100 females age 18 and over, there were 100.0 males.

The median income for a household in the town was $75,487, and the median income for a family was $0. Males had a median income of $0 versus $0 for females. The per capita income for the town was $79,000. None of the population or families were below the poverty line.



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