Cowley, Wyoming

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Cowley is a town in Big Horn County, Wyoming, United States. The population was 560 at the 2000 census.



Cowley is located at 44°52′58″N 108°28′5″W / 44.88278°N 108.46806°W / 44.88278; -108.46806 (44.882684, -108.468193)[3].

According to the United States Census Bureau, the town has a total area of 0.7 square miles (1.8 km²), all of it land.


As of the census[1] of 2000, there were 560 people, 200 households, and 160 families residing in the town. The population density was 796.5 people per square mile (308.9/km²). There were 223 housing units at an average density of 317.2/sq mi (123.0/km²). The racial makeup of the town was 97.32% White, 0.18% Asian, 2.14% from other races, and 0.36% from two or more races. Hispanic or Latino of any race were 3.39% of the population.

There were 200 households out of which 41.0% had children under the age of 18 living with them, 70.0% were married couples living together, 7.5% had a female householder with no husband present, and 20.0% were non-families. 18.5% of all households were made up of individuals and 9.0% had someone living alone who was 65 years of age or older. The average household size was 2.80 and the average family size was 3.19.

In the town the population was spread out with 31.1% under the age of 18, 9.3% from 18 to 24, 24.5% from 25 to 44, 22.1% from 45 to 64, and 13.0% who were 65 years of age or older. The median age was 34 years. For every 100 females there were 97.9 males. For every 100 females age 18 and over, there were 96.9 males.

The median income for a household in the town was $38,750, and the median income for a family was $39,722. Males had a median income of $31,848 versus $20,000 for females. The per capita income for the town was $14,964. About 3.8% of families and 7.2% of the population were below the poverty line, including 10.3% of those under age 18 and 7.8% of those age 65 or over.

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