Danbury, Nebraska

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Danbury is a village in Red Willow County, Nebraska, United States. The population was 127 at the 2000 census.

Geography

Danbury is located at 40°2′20″N 100°24′22″W / 40.03889°N 100.40611°W / 40.03889; -100.40611 (40.038756, -100.406129)[3].

According to the United States Census Bureau, the village has a total area of 0.3 square miles (0.9 km²), all of it land.

Demographics

As of the census[1] of 2000, there were 127 people, 54 households, and 38 families residing in the village. The population density was 378.7 people per square mile (144.2/km²). There were 60 housing units at an average density of 178.9/sq mi (68.1/km²). The racial makeup of the village was 100.00% White. Hispanic or Latino of any race were 0.79% of the population.

There were 54 households out of which 24.1% had children under the age of 18 living with them, 68.5% were married couples living together, 1.9% had a female householder with no husband present, and 29.6% were non-families. 25.9% of all households were made up of individuals and 13.0% had someone living alone who was 65 years of age or older. The average household size was 2.35 and the average family size was 2.87.

In the village the population spread was 25.2% of the population under the age of 18, 3.9% from 18 to 24, 26.0% from 25 to 44, 25.2% from 45 to 64, and 19.7% who were 65 years of age or older. The median age was 42 years. For every 100 females there were 98.4 males. For every 100 females age 18 and over, there were 111.1 males.

The median income for a household in the village was $33,750, and the median income for a family was $44,583. Males had a median income of $24,464 versus $18,958 for females. The per capita income for the village was $19,512. There were 4.9% of families and 8.4% of the population living below the poverty line, including no under eighteens and 19.0% of those over 64.

References

Indianola | McCook

Bartley | Danbury | Lebanon

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