Dayton, Iowa

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Dayton is a city in Webster County, Iowa, United States. The population was 884 at the 2000 census.



Dayton is located at 42°15′46″N 94°4′9″W / 42.26278°N 94.06917°W / 42.26278; -94.06917 (42.262672, -94.069136)[1].

According to the United States Census Bureau, the city has a total area of 0.8 square miles (2.1 km²), all of it land.


As of the census[2] of 2000, there were 884 people, 354 households, and 235 families residing in the city. The population density was 1,062.8 people per square mile (411.2/km²). There were 379 housing units at an average density of 455.7/sq mi (176.3/km²). The racial makeup of the city was 98.42% White, 0.11% African American, 0.11% Native American, 0.23% Asian, 0.45% from other races, and 0.68% from two or more races. Hispanic or Latino of any race were 0.34% of the population.

There were 354 households out of which 29.9% had children under the age of 18 living with them, 53.4% were married couples living together, 9.3% had a female householder with no husband present, and 33.6% were non-families. 30.2% of all households were made up of individuals and 15.5% had someone living alone who was 65 years of age or older. The average household size was 2.38 and the average family size was 2.91.

In the city the population was spread out with 24.8% under the age of 18, 7.6% from 18 to 24, 24.2% from 25 to 44, 18.1% from 45 to 64, and 25.3% who were 65 years of age or older. The median age was 40 years. For every 100 females there were 91.3 males. For every 100 females age 18 and over, there were 87.3 males.

The median income for a household in the city was $33,864, and the median income for a family was $38,698. Males had a median income of $30,952 versus $20,208 for females. The per capita income for the city was $15,714. About 13.9% of families and 11.5% of the population were below the poverty line, including 15.8% of those under age 18 and 6.1% of those age 65 or over.

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