Delaware, Iowa

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Delaware is a city in Delaware County, Iowa, United States. The population was 188 at the 2000 census.


Delaware is located at 42°28′26″N 91°20′32″W / 42.47389°N 91.34222°W / 42.47389; -91.34222 (42.473959, -91.342283)[1].

According to the United States Census Bureau, the city has a total area of 0.8 square miles (2.1 km²), of which, 0.8 square miles (2.1 km²) of it is land and 1.23% is water.


As of the census[2] of 2000, there were 188 people, 78 households, and 51 families residing in the city. The population density was 235.4 people per square mile (90.7/km²). There were 78 housing units at an average density of 97.7/sq mi (37.6/km²). The racial makeup of the city was 98.94% White, and 1.06% from two or more races. Hispanic or Latino of any race were 1.06% of the population.

There were 78 households out of which 32.1% had children under the age of 18 living with them, 51.3% were married couples living together, 11.5% had a female householder with no husband present, and 34.6% were non-families. 26.9% of all households were made up of individuals and 11.5% had someone living alone who was 65 years of age or older. The average household size was 2.41 and the average family size was 2.82.

In the city the population was spread out with 29.3% under the age of 18, 5.9% from 18 to 24, 31.9% from 25 to 44, 22.3% from 45 to 64, and 10.6% who were 65 years of age or older. The median age was 35 years. For every 100 females there were 100.0 males. For every 100 females age 18 and over, there were 98.5 males.

The median income for a household in the city was $36,875, and the median income for a family was $40,694. Males had a median income of $31,250 versus $21,875 for females. The per capita income for the city was $18,361. None of the families and 4.4% of the population were living below the poverty line, including no under eighteens and 16.7% of those over 64.


Colesburg | Delaware | Delhi | Dundee | Dyersville‡ | Earlville | Edgewood‡ | Greeley | Hopkinton | Manchester | Masonville | Ryan

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