Dillonvale, Jefferson County, Ohio

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Dillonvale is a village in Jefferson County, Ohio, United States. The population was 781 at the 2000 census. It is part of the WeirtonSteubenville, WV-OH Metropolitan Statistical Area.



Dillonvale is located at 40°11′53″N 80°46′24″W / 40.19806°N 80.77333°W / 40.19806; -80.77333 (40.198181, -80.773376)[3].

According to the United States Census Bureau, the village has a total area of 0.4 square miles (1.1 km²), of which, 0.4 square miles (1.1 km²) of it is land and 2.38% is water.


As of the census[2] of 2000, there were 781 people, 339 households, and 234 families residing in the village. The population density was 1,889.6 people per square mile (735.5/km²). There were 392 housing units at an average density of 948.4/sq mi (369.2/km²). The racial makeup of the village was 98.46% White, 0.51% African American, 0.13% Asian, and 0.90% from two or more races.

There were 339 households out of which 25.7% had children under the age of 18 living with them, 48.1% were married couples living together, 13.9% had a female householder with no husband present, and 30.7% were non-families. 28.6% of all households were made up of individuals and 18.0% had someone living alone who was 65 years of age or older. The average household size was 2.30 and the average family size was 2.74.

In the village the population was spread out with 20.2% under the age of 18, 7.6% from 18 to 24, 25.1% from 25 to 44, 22.0% from 45 to 64, and 25.1% who were 65 years of age or older. The median age was 43 years. For every 100 females there were 87.7 males. For every 100 females age 18 and over, there were 83.8 males.

The median income for a household in the village was $28,636, and the median income for a family was $34,625. Males had a median income of $29,500 versus $19,615 for females. The per capita income for the village was $14,446. About 8.5% of families and 11.9% of the population were below the poverty line, including 13.2% of those under age 18 and 10.3% of those age 65 or over.

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