Dundee, Florida

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Dundee is a town in Polk County, Florida, United States. The population was 2,912 at the 2000 census. As of 2004, the population recorded by the U.S. Census Bureau is 3,008 [1]. It is part of the LakelandWinter Haven Metropolitan Statistical Area.

Contents

Geography and climate

Dundee is located at 28°1′15″N 81°37′15″W / 28.02083°N 81.62083°W / 28.02083; -81.62083 (28.020837, -81.620783)[4].

According to the United States Census Bureau, the town has a total area of 11.2 km² (4.3 mi²). 10.2 km² (3.9 mi²) of it is land and 1.0 km² (0.4 mi²) of it (8.82%) is water.

Dundee is located in the humid subtropical zone (Köppen climate classification: Cfa).[5]

Demographics

As of the census[2] of 2000, there were 2,912 people, 1,123 households, and 811 families residing in the town. The population density was 286.1/km² (740.7/mi²). There were 1,457 housing units at an average density of 143.1/km² (370.6/mi²). The racial makeup of the town was 69.92% White, 22.05% African American, 0.14% Native American, 0.93% Asian, 0.03% Pacific Islander, 5.56% from other races, and 1.37% from two or more races. Hispanic or Latino of any race were 11.37% of the population.

There were 1,123 households out of which 28.3% had children under the age of 18 living with them, 55.7% were married couples living together, 13.2% had a female householder with no husband present, and 27.7% were non-families. 24.1% of all households were made up of individuals and 14.3% had someone living alone who was 65 years of age or older. The average household size was 2.57 and the average family size was 3.04.

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