Dune Acres, Indiana

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Dune Acres is a town in Westchester Township, Porter County, Indiana, United States. The population was 213 at the 2000 census.

Contents

Geography

Dune Acres is located at 41°38′47″N 87°5′6″W / 41.64639°N 87.085°W / 41.64639; -87.085 (41.646416, -87.084905)[3].

According to the United States Census Bureau, the town has a total area of 3.5 square miles (9.1 km²), of which, 2.1 square miles (5.5 km²) of it is land and 1.4 square miles (3.6 km²) of it (39.20%) is water.

Demographics

As of the census[1] of 2000, there were 213 people, 101 households, and 76 families residing in the town. The population density was 99.7 people per square mile (38.4/km²). There were 154 housing units at an average density of 72.0/sq mi (27.8/km²). The racial makeup of the town was 99.06% White, and 0.94% from two or more races. Hispanic or Latino of any race were 1.41% of the population.

There were 101 households out of which 13.9% had children under the age of 18 living with them, 67.3% were married couples living together, 5.0% had a female householder with no husband present, and 23.8% were non-families. 20.8% of all households were made up of individuals and 13.9% had someone living alone who was 65 years of age or older. The average household size was 2.11 and the average family size was 2.39.

In the town the population was spread out with 11.7% under the age of 18, 3.3% from 18 to 24, 13.1% from 25 to 44, 33.8% from 45 to 64, and 38.0% who were 65 years of age or older. The median age was 60 years. For every 100 females there were 104.8 males. For every 100 females age 18 and over, there were 97.9 males.

The median income for a household in the town was $94,843, and the median income for a family was $102,524. Males had a median income of $83,632 versus $41,250 for females. The per capita income for the town was $68,051. None of the population or families were below the poverty line.

Famous former resident of Dune Acres

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