Dyersville, Iowa

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Dyersville is a city in eastern Delaware and western Dubuque Counties in the U.S. state of Iowa. It is part of the Dubuque, Iowa, Metropolitan Statistical Area. The population was 4,035 at the 2000 census and was estimated to be 4,167 in 2006.[2]

Local attractions in Dyersville include:



Dyersville is located at 42°28′53″N 91°7′15″W / 42.48139°N 91.12083°W / 42.48139; -91.12083 (42.481316, -91.120967),[3] along the North Fork of the Maquoketa River.

According to the United States Census Bureau, the city has a total area of 4.6 square miles (11.9 km²), of which, 4.6 square miles (11.9 km²) of it is land and 0.22% is water.


As of the census[4] of 2000, there were 4,035 people, 1,578 households, and 1,117 families residing in the city. The population density was 878.1 people per square mile (338.7/km²). There were 1,669 housing units at an average density of 363.2/sq mi (140.1/km²). The racial makeup of the city was 98.71% White, 0.45% African American, 0.17% Pacific Islander, 0.12% Asian, 0.05% from other races, and 0.50% from two or more races. Hispanic or Latino of any race were 0.45% of the population.

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