Ellsworth, Iowa

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Ellsworth is a city in Hamilton County, Iowa, United States. The population was 531 at the 2000 census.



Ellsworth is located at 42°18′43″N 93°34′51″W / 42.31194°N 93.58083°W / 42.31194; -93.58083 (42.311954, -93.580868)[1].

According to the United States Census Bureau, the city has a total area of 0.9 square miles (2.3 km²), all of it land.


As of the census[2] of 2000, there were 531 people, 204 households, and 138 families residing in the city. The population density was 589.9 people per square mile (227.8/km²). There were 219 housing units at an average density of 243.3/sq mi (94.0/km²). The racial makeup of the city was 91.90% White, 1.32% Native American, 6.03% from other races, and 0.75% from two or more races. Hispanic or Latino of any race were 11.49% of the population.

There were 204 households out of which 34.8% had children under the age of 18 living with them, 54.4% were married couples living together, 11.8% had a female householder with no husband present, and 31.9% were non-families. 27.0% of all households were made up of individuals and 15.7% had someone living alone who was 65 years of age or older. The average household size was 2.60 and the average family size was 3.17.

In the city the population was spread out with 29.4% under the age of 18, 10.5% from 18 to 24, 29.4% from 25 to 44, 15.4% from 45 to 64, and 15.3% who were 65 years of age or older. The median age was 32 years. For every 100 females there were 92.4 males. For every 100 females age 18 and over, there were 89.4 males.

The median income for a household in the city was $30,893, and the median income for a family was $36,250. Males had a median income of $28,365 versus $21,250 for females. The per capita income for the city was $15,299. About 8.3% of families and 11.2% of the population were below the poverty line, including 16.5% of those under age 18 and 11.0% of those age 65 or over.


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