Essex, Iowa

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Essex is a city in Page County, Iowa, United States. The population was 884 at the 2000 census.



Essex is located at 40°49′59″N 95°18′19″W / 40.83306°N 95.30528°W / 40.83306; -95.30528 (40.833016, -95.305208)[1] near the East Nishnabotna River.

According to the United States Census Bureau, the city has a total area of 1.5 square miles (3.9 km²), all of it land.


As of the census[2] of 2000, there were 884 people, 356 households, and 260 families residing in the city. The population density was 586.7 people per square mile (226.0/km²). There were 393 housing units at an average density of 260.8/sq mi (100.5/km²). The racial makeup of the city was 97.85% White, 0.57% Native American, 0.34% from other races, and 1.24% from two or more races. Hispanic or Latino of any race were 0.68% of the population.

There were 356 households out of which 31.5% had children under the age of 18 living with them, 62.6% were married couples living together, 7.0% had a female householder with no husband present, and 26.7% were non-families. 23.6% of all households were made up of individuals and 13.2% had someone living alone who was 65 years of age or older. The average household size was 2.48 and the average family size was 2.94.

In the city the population was spread out with 25.3% under the age of 18, 5.5% from 18 to 24, 25.6% from 25 to 44, 25.3% from 45 to 64, and 18.2% who were 65 years of age or older. The median age was 39 years. For every 100 females there were 100.0 males. For every 100 females age 18 and over, there were 101.2 males.

The median income for a household in the city was $41,382, and the median income for a family was $51,806. Males had a median income of $36,118 versus $22,604 for females. The per capita income for the city was $18,202. About 3.2% of families and 5.5% of the population were below the poverty line, including 7.4% of those under age 18 and 7.9% of those age 65 or over.


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