Florien, Louisiana

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Florien is a village in Sabine Parish, Louisiana, United States. The population was 692 at the 2000 census.

Contents

Geography

Florien is located at 31°26′35″N 93°27′29″W / 31.44306°N 93.45806°W / 31.44306; -93.45806 (31.443145, -93.457999)[1].

According to the United States Census Bureau, the village has a total area of 5.8 km² (2.2 mi²), all land.

Demographics

As of the census[2] of 2000, there were 692 people, 258 households, and 190 families residing in the village. The population density was 120.4/km² (311.5/mi²). There were 312 housing units at an average density of 54.3/km² (140.4/mi²). The racial makeup of the village was 71.24% White, 27.02% African American, 0.87% Native American, 0.14% from other races, and 0.72% from two or more races. Hispanic or Latino of any race were 2.02% of the population.

There were 258 households out of which 41.9% had children under the age of 18 living with them, 55.4% were married couples living together, 15.5% had a female householder with no husband present, and 26.0% were non-families. 24.4% of all households were made up of individuals and 10.9% had someone living alone who was 65 years of age or older. The average household size was 2.68 and the average family size was 3.19.

In the village the population was spread out with 30.8% under the age of 18, 8.5% from 18 to 24, 29.2% from 25 to 44, 20.8% from 45 to 64, and 10.7% who were 65 years of age or older. The median age was 33 years. For every 100 females there were 85.0 males. For every 100 females age 18 and over, there were 84.9 males.

The median income for a household in the village was $22,153, and the median income for a family was $25,833. Males had a median income of $29,375 versus $16,354 for females. The per capita income for the village was $10,855. About 21.4% of families and 24.8% of the population were below the poverty line, including 34.1% of those under age 18 and 7.9% of those age 65 or over.

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