Floyd, New York

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Floyd is a town in Oneida County, New York, United States. The population was 3,869 at the 2000 census. The town is named after William Floyd, a signer of the Declaration of Independence.

The Town of Floyd is located east of the City of Rome and the former Griffiss Air Force Base.

The Erie Canal passes along the south part of the town.



The area was first settled around 1790. The Town of Floyd was founded in 1796 from the Town of Steuben. William Floyd, for whom the town is named, became a resident of Oneida County in 1794.

The population of Floyd was 663 in 1920.


According to the United States Census Bureau, the town has a total area of 34.8 square miles (90.0 km²), of which, 34.6 square miles (89.6 km²) of it is land and 0.2 square miles (0.4 km²) of it (0.46%) is water.

The Mohawk River defines the south town line.


As of the census[1] of 2000, there were 3,869 people, 1,394 households, and 1,091 families residing in the town. The population density was 111.8 people per square mile (43.2/km²). There were 1,483 housing units at an average density of 42.9/sq mi (16.5/km²). The racial makeup of the town was 97.49% White, 0.36% African American, 0.18% Native American, 0.41% Asian, 0.08% Pacific Islander, 0.18% from other races, and 1.29% from two or more races. Hispanic or Latino of any race were 1.03% of the population.

There were 1,394 households out of which 38.8% had children under the age of 18 living with them, 63.0% were married couples living together, 10.4% had a female householder with no male present, and 21.7% were non-families. 17.3% of all households were made up of individuals and 7.4% had someone living alone who was 65 years of age or older. The average household size was 2.78 and the average family size was 3.11.

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