Frankfort, South Dakota

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Frankfort is a city in Spink County, South Dakota, United States. The population was 166 at the 2000 census.



Frankfort is located at 44°52′39″N 98°18′22″W / 44.8775°N 98.30611°W / 44.8775; -98.30611 (44.877368, -98.306068)[3].

According to the United States Census Bureau, the city has a total area of 0.8 square miles (2.0 km²), all of it land.

Frankfort has been assigned the ZIP code 57440 and the FIPS place code 22580.


As of the census[1] of 2000, there were 166 people, 81 households, and 43 families residing in the city. The population density was 214.4 people per square mile (83.2/km²). There were 99 housing units at an average density of 127.9/sq mi (49.6/km²). The racial makeup of the city was 98.80% White, 0.60% Native American, 0.60% from other races. Hispanic or Latino of any race were 0.60% of the population.

There were 81 households out of which 18.5% had children under the age of 18 living with them, 48.1% were married couples living together, 4.9% had a female householder with no husband present, and 46.9% were non-families. 40.7% of all households were made up of individuals and 14.8% had someone living alone who was 65 years of age or older. The average household size was 2.05 and the average family size was 2.84.

In the city the population was spread out with 20.5% under the age of 18, 6.6% from 18 to 24, 15.7% from 25 to 44, 31.9% from 45 to 64, and 25.3% who were 65 years of age or older. The median age was 49 years. For every 100 females there were 115.6 males. For every 100 females age 18 and over, there were 109.5 males.

The median income for a household in the city was $30,357, and the median income for a family was $39,688. Males had a median income of $22,500 versus $17,000 for females. The per capita income for the city was $14,989. About 4.3% of families and 9.2% of the population were below the poverty line, including 18.8% of those under the age of eighteen and 12.2% of those sixty five or over.

Notable natives

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