French Camp, Mississippi

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French Camp is a town in Choctaw County, Mississippi, United States. The population was 393 at the 2000 census.

Contents

Geography

French Camp is located at 33°17′38″N 89°24′1″W / 33.29389°N 89.40028°W / 33.29389; -89.40028 (33.293936, -89.400248)[1].

According to the United States Census Bureau, the town has a total area of 1.0 square miles (2.6 km²), all of it land.

Demographics

As of the census[2] of 2000, there were 393 people, 68 households, and 42 families residing in the town. The population density was 398.1 people per square mile (153.3/km²). There were 74 housing units at an average density of 75.0/sq mi (28.9/km²). The racial makeup of the town was 92.37% White, 5.09% African American, 1.53% from other races, and 1.02% from two or more races. Hispanic or Latino of any race were 1.27% of the population.

There were 68 households out of which 26.5% had children under the age of 18 living with them, 54.4% were married couples living together, 4.4% had a female householder with no husband present, and 36.8% were non-families. 36.8% of all households were made up of individuals and 17.6% had someone living alone who was 65 years of age or older. The average household size was 2.43 and the average family size was 3.19.

In the town the population was spread out with 48.6% under the age of 18, 9.4% from 18 to 24, 13.5% from 25 to 44, 16.5% from 45 to 64, and 12.0% who were 65 years of age or older. The median age was 18 years. For every 100 females there were 113.6 males. For every 100 females age 18 and over, there were 96.1 males.

The median income for a household in the town was $26,250, and the median income for a family was $27,188. Males had a median income of $13,750 versus $12,813 for females. The per capita income for the town was $5,047. About 17.1% of families and 64.5% of the population were below the poverty line, including 70.5% of those under age 18 and none of those age 65 or over.

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