Fulton, Indiana

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Fulton is a town in Liberty Township, Fulton County, Indiana, United States. The population was 326 at the 2000 census.


Fulton is located at 40°56′50″N 86°15′50″W / 40.94722°N 86.26389°W / 40.94722; -86.26389 (40.947157, -86.263935)[3].

According to the United States Census Bureau, the town has a total area of 0.2 square miles (0.5 km²), all of it land.


As of the census[1] of 2000, there were 326 people, 127 households, and 93 families residing in the town. The population density was 1,797.9 people per square mile (699.3/km²). There were 142 housing units at an average density of 783.1/sq mi (304.6/km²). The racial makeup of the town was 99.69% White, 0.31% from other races.

There were 127 households out of which 37.0% had children under the age of 18 living with them, 63.8% were married couples living together, 7.1% had a female householder with no husband present, and 26.0% were non-families. 24.4% of all households were made up of individuals and 11.8% had someone living alone who was 65 years of age or older. The average household size was 2.57 and the average family size was 3.04.

In the town the population was spread out with 26.7% under the age of 18, 7.7% from 18 to 24, 32.5% from 25 to 44, 17.8% from 45 to 64, and 15.3% who were 65 years of age or older. The median age was 34 years. For every 100 females there were 97.6 males. For every 100 females age 18 and over, there were 89.7 males.

The median income for a household in the town was $44,375, and the median income for a family was $47,500. Males had a median income of $32,045 versus $25,547 for females. The per capita income for the town was $16,732. About 3.3% of families and 2.4% of the population were below the poverty line, including 2.5% of those under age 18 and none of those age 65 or over.



Akron | Fulton | Kewanna

Aubbeenaubbee | Henry | Liberty | Newcastle | Richland | Rochester | Union | Wayne

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