Gilbertsville, New York

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Gilbertsville is a village in Otsego County, New York, United States. The population was 375 at the 2000 census. The village is named after its founder, and early landowner Abijah Gilbert of Nuneaton, England, father of the eponymous United States Senator from Florida.

The Village of Gilbertsville is in the Town of Butternuts and is west of Oneonta.

Contents

Geography

Gilbertsville is located at 42°28′10″N 75°19′16″W / 42.46944°N 75.32111°W / 42.46944; -75.32111 (42.469492, -75.320980)[1].

According to the United States Census Bureau, the village has a total area of 1.0 square miles (2.6 km²), all of it land.

Gilbertsville is located on New York State Route 51 (Marion Avenue) and is also served by County Highways 4 (Cliff Street and Bloom Street) and 8 (Vale Street).

Gilbertsville is located by the Butternut Creek.

Demographics

As of the census[2] of 2000, there were 375 people, 164 households, and 103 families residing in the village. The population density was 374.0 people per square mile (144.8/km²). There were 196 housing units at an average density of 195.5/sq mi (75.7/km²). The racial makeup of the village was 96.27% White, 0.80% African American, 0.80% Native American, 0.27% Asian, and 1.87% from two or more races. Hispanic or Latino of any race were 1.33% of the population.

There were 164 households out of which 25.0% had children under the age of 18 living with them, 51.8% were married couples living together, 9.1% had a female householder with no husband present, and 36.6% were non-families. 31.7% of all households were made up of individuals and 20.1% had someone living alone who was 65 years of age or older. The average household size was 2.27 and the average family size was 2.88.

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