Graf, Iowa

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Graf is a city in Dubuque County, Iowa, United States. It is part of the 'Dubuque, Iowa Metropolitan Statistical Area'. The population was 73 at the 2000 census.


Graf is located at 42°29′42″N 90°52′19″W / 42.495°N 90.87194°W / 42.495; -90.87194 (42.494967, -90.872077)[1].

According to the United States Census Bureau, the city has a total area of 0.1 square miles (0.4 km²), all of it land.


As of the census[2] of 2000, there were 73 people, 23 households, and 22 families residing in the city. The population density was 521.4 people per square mile (201.3/km²). There were 23 housing units at an average density of 164.3/sq mi (63.4/km²). The racial makeup of the city was 100.00% White.

There were 23 households out of which 56.5% had children under the age of 18 living with them, 78.3% were married couples living together, 4.3% had a female householder with no husband present, and 4.3% were non-families. 4.3% of all households were made up of individuals and 4.3% had someone living alone who was 65 years of age or older. The average household size was 3.17 and the average family size was 3.23.

In the city the population was spread out with 30.1% under the age of 18, 11.0% from 18 to 24, 26.0% from 25 to 44, 26.0% from 45 to 64, and 6.8% who were 65 years of age or older. The median age was 34 years. For every 100 females there were 97.3 males. For every 100 females age 18 and over, there were 121.7 males.

The median income for a household in the city was $56,250, and the median income for a family was $56,250. Males had a median income of $35,000 versus $24,250 for females. The per capita income for the city was $14,438. None of the population and none of the families were below the poverty line.


Asbury | Balltown | Bankston | Bernard | Cascade‡ | Centralia | Dubuque | Durango | Dyersville‡ | Epworth | Farley | Graf | Holy Cross | Luxemburg | New Vienna | Peosta | Rickardsville | Sageville | Sherrill | Worthington | Zwingle

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