Greybull, Wyoming

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Greybull is a town in Big Horn County, Wyoming, United States. The population was 1,815 at the 2000 census.

Contents

Geography

Greybull is located at 44°29′29″N 108°3′13″W / 44.49139°N 108.05361°W / 44.49139; -108.05361 (44.491450, -108.053655)[3].

According to the United States Census Bureau, the town has a total area of 1.8 square miles (4.6 km²), of which, 1.8 square miles (4.6 km²) of it is land and 0.56% is water.

Demographics

As of the census[1] of 2000, there were 1,815 people, 781 households, and 500 families residing in the town. The population density was 1,018.4 people per square mile (393.7/km²). There were 923 housing units at an average density of 517.9/sq mi (200.2/km²). The racial makeup of the town was 96.20% White, 0.11% African American, 0.83% Native American, 0.39% Asian, 1.32% from other races, and 1.16% from two or more races. Hispanic or Latino of any race were 4.74% of the population.

There were 781 households out of which 28.6% had children under the age of 18 living with them, 51.7% were married couples living together, 7.6% had a female householder with no husband present, and 35.9% were non-families. 32.0% of all households were made up of individuals and 14.5% had someone living alone who was 65 years of age or older. The average household size was 2.32 and the average family size was 2.92.

In the town the population was spread out with 26.6% under the age of 18, 7.3% from 18 to 24, 23.5% from 25 to 44, 25.6% from 45 to 64, and 17.1% who were 65 years of age or older. The median age was 40 years. For every 100 females there were 96.2 males. For every 100 females age 18 and over, there were 95.5 males.

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