Hardin, Montana

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Hardin is a city in and the county seat of Big Horn County, Montana, United States.[1] The population was 3,384 at the 2000 census.



The city was named for Samuel Hardin, a friend of developer Charles Henry Morrill.[2]


Hardin is located at 45°43′55″N 107°36′45″W / 45.73194°N 107.6125°W / 45.73194; -107.6125 (45.731824, -107.612542).[3]

According to the United States Census Bureau, the city has a total area of 1.4 square miles (3.6 km²), all of it land.


As of the census[4] of 2000, there were 3,384 people, 1,295 households, and 868 families residing in the city. The population density was 2,415.5 people per square mile (933.3/km²). There were 1,411 housing units at an average density of 1,007.2/sq mi (389.1/km²). The racial makeup of the city was 62.26% White, 0.12% African American, 31.59% Native American, 0.35% Asian, 1.03% from other races, and 4.64% from two or more races. Hispanic or Latino of any race were 5.53% of the population.

There were 1,295 households out of which 36.2% had children under the age of 18 living with them, 46.3% were married couples living together, 16.6% had a female householder with no husband present, and 32.9% were non-families. 29.2% of all households were made up of individuals and 12.7% had someone living alone who was 65 years of age or older. The average household size was 2.55 and the average family size was 3.16.

In the city the population was spread out with 31.0% under the age of 18, 7.7% from 18 to 24, 26.3% from 25 to 44, 21.1% from 45 to 64, and 13.9% who were 65 years of age or older. The median age was 34 years. For every 100 females there were 88.8 males. For every 100 females age 18 and over, there were 79.6 males.

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