Hardinsburg, Kentucky

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Hardinsburg is a city in Breckinridge County, Kentucky, United States. The population was 2,345 at the 2000 census. It is the county seat of Breckinridge County.[2] By Kentucky state law, it is classified as a fifth class city. The city's namesake, Captain William Hardin, established the city as a frontier fort in 1780.[3]



Hardinsburg is located at 37°46′35″N 86°27′18″W / 37.77639°N 86.455°W / 37.77639; -86.455 (37.776336, -86.455010).[4]

According to the United States Census Bureau, the city has a total area of 3.6 square miles (9.4 km²), of which, 3.6 square miles (9.2 km²) of it is land and 0.1 square miles (0.2 km²) of it (1.65%) is water.


As of the census[5] of 2000, there were 2,345 people, 964 households, and 583 families residing in the city. The population density was 658.1 people per square mile (254.3/km²). There were 1,078 housing units at an average density of 302.5/sq mi (116.9/km²). The racial makeup of the city was 90.06% White, 8.61% African American, 0.17% Native American, 0.09% Asian, 0.13% from other races, and 0.94% from two or more races. Hispanic or Latino of any race were 1.41% of the population.

There were 964 households out of which 25.1% had children under the age of 18 living with them, 43.8% were married couples living together, 13.4% had a female householder with no husband present, and 39.5% were non-families. 36.8% of all households were made up of individuals and 19.1% had someone living alone who was 65 years of age or older. The average household size was 2.19 and the average family size was 2.83.

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