Harper, Iowa

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Harper is a city in Keokuk County, Iowa, United States. The population was 134 at the 2000 census.

Geography

Harper is located at 41°21′48″N 92°3′5″W / 41.36333°N 92.05139°W / 41.36333; -92.05139 (41.363351, -92.051379)[1].

According to the United States Census Bureau, the city has a total area of 0.1 square miles (0.2 km²), all of it land.

Demographics

As of the census[2] of 2000, there were 134 people, 55 households, and 40 families residing in the city. The population density was 1,523.7 people per square mile (574.9/km²). There were 61 housing units at an average density of 693.6/sq mi (261.7/km²). The racial makeup of the city was 100.00% White.

There were 55 households out of which 27.3% had children under the age of 18 living with them, 65.5% were married couples living together, 5.5% had a female householder with no husband present, and 25.5% were non-families. 20.0% of all households were made up of individuals and 12.7% had someone living alone who was 65 years of age or older. The average household size was 2.44 and the average family size was 2.78.

In the city the population was spread out with 23.9% under the age of 18, 3.7% from 18 to 24, 28.4% from 25 to 44, 15.7% from 45 to 64, and 28.4% who were 65 years of age or older. The median age was 40 years. For every 100 females there were 91.4 males. For every 100 females age 18 and over, there were 100.0 males.

The median income for a household in the city was $37,875, and the median income for a family was $38,594. Males had a median income of $22,083 versus $22,188 for females. The per capita income for the city was $12,620. There were 4.9% of families and 4.5% of the population living below the poverty line, including 3.9% of under eighteens and none of those over 64.

References

Delta | Gibson | Harper | Hayesville | Hedrick | Keota | Keswick | Kinross | Martinsburg | North English‡ | Ollie | Richland | Sigourney | South English | Thornburg | Webster | What Cheer

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