Hartland, Wisconsin

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Hartland is a village in Waukesha County, Wisconsin, along the Bark River, and is a suburb of Milwaukee. The population was estimated at 8,689 in 2006.



Hartland is located at 43°6′1″N 88°20′40″W / 43.10028°N 88.34444°W / 43.10028; -88.34444 (43.100180, -88.344452).[3] It is in the Lake Country area of Waukesha County.

According to the United States Census Bureau, the village has a total area of 4.5 square miles (11.7 km²), of which, 4.5 square miles (11.7 km²) of it is land and 0.22% is water.


As of the census[2] of 2000, there were 7,905 people, 3,002 households, and 2,161 families residing in the village. The population density was 1,753.7 people per square mile (676.7/km²). There were 3,140 housing units at an average density of 696.6/sq mi (268.8/km²). The racial makeup of the village was 97.70% White, 0.28% African American, 0.33% Native American, 0.48% Asian, 0.43% from other races, and 0.78% from two or more races. Hispanic or Latino of any race were 1.51% of the population.

There were 3,002 households out of which 41.3% had children under the age of 18 living with them, 57.4% were married couples living together, 11.0% had a female householder with no husband present, and 28.0% were non-families. 22.3% of all households were made up of individuals and 7.2% had someone living alone who was 65 years of age or older. The average household size was 2.63 and the average family size was 3.13.

In the village the population was spread out with 29.7% under the age of 18, 7.8% from 18 to 24, 33.5% from 25 to 44, 21.5% from 45 to 64, and 7.5% who were 65 years of age or older. The median age was 34 years. For every 100 females there were 93.7 males. For every 100 females age 18 and over, there were 92.7 males.

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