Hartville, Wyoming

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Hartville is a town in Platte County, Wyoming, United States. The population was 76 at the 2000 census.



Hartville is located at 42°19′36″N 104°43′40″W / 42.32667°N 104.72778°W / 42.32667; -104.72778 (42.326783, -104.727790)[3].

According to the United States Census Bureau, the town has a total area of 0.3 square miles (0.7 km²), all of it land.


As of the census[1] of 2000, there were 76 people, 35 households, and 22 families residing in the town. The population density was 272.2 people per square mile (104.8/km²). There were 52 housing units at an average density of 186.2/sq mi (71.7/km²). The racial makeup of the town was 89.47% White, 6.58% from other races, and 3.95% from two or more races. Hispanic or Latino of any race were 22.37% of the population.

There were 35 households out of which 25.7% had children under the age of 18 living with them, 54.3% were married couples living together, 8.6% had a female householder with no husband present, and 37.1% were non-families. 37.1% of all households were made up of individuals and 14.3% had someone living alone who was 65 years of age or older. The average household size was 2.17 and the average family size was 2.82.

In the town the population was spread out with 23.7% under the age of 18, 1.3% from 18 to 24, 22.4% from 25 to 44, 18.4% from 45 to 64, and 34.2% who were 65 years of age or older. The median age was 51 years. For every 100 females there were 100.0 males. For every 100 females age 18 and over, there were 93.3 males.

The median income for a household in the town was $25,000, and the median income for a family was $13,750. Males had a median income of $26,667 versus $0 for females. The per capita income for the town was $12,116. There were 36.4% of families and 28.4% of the population living below the poverty line, including 35.3% of under eighteens and 20.0% of those over 64.

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