Hartwick, Iowa

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Hartwick is a city in Poweshiek County, Iowa, United States. The population was 83 at the 2000 census.

Geography

Hartwick is located at 41°47′7″N 92°20′39″W / 41.78528°N 92.34417°W / 41.78528; -92.34417 (41.785264, -92.344290)[1].

According to the United States Census Bureau, the city has a total area of 0.1 square miles (0.3 km²), all of it land.

Demographics

As of the census[2] of 2000, there were 83 people, 36 households, and 24 families residing in the city. The population density was 640.7 people per square mile (246.5/km²). There were 40 housing units at an average density of 308.8/sq mi (118.8/km²). The racial makeup of the city was 100.00% White.

There were 36 households out of which 27.8% had children under the age of 18 living with them, 66.7% were married couples living together, 2.8% had a female householder with no husband present, and 30.6% were non-families. 27.8% of all households were made up of individuals and 19.4% had someone living alone who was 65 years of age or older. The average household size was 2.31 and the average family size was 2.84.

In the city the population was spread out with 20.5% under the age of 18, 7.2% from 18 to 24, 26.5% from 25 to 44, 26.5% from 45 to 64, and 19.3% who were 65 years of age or older. The median age was 40 years. For every 100 females there were 88.6 males. For every 100 females age 18 and over, there were 83.3 males.

The median income for a household in the city was $36,250, and the median income for a family was $43,750. Males had a median income of $33,750 versus $21,875 for females. The per capita income for the city was $18,830. There were no families and 2.7% of the population living below the poverty line, including no under eighteens and none of those over 64.

References

Barnes City | Brooklyn | Deep River | Grinnell | Guernsey | Hartwick | Malcom | Montezuma | Searsboro

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