Haywood County, Tennessee

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Haywood County is a county located in the U.S. state of Tennessee. In 2000, its population was 19,797. For 2005, the U.S. Census Bureau estimated that its population was 19,656.[1] Its county seat is Brownsville[2].



According to the U.S. Census Bureau, the county has a total area of 534 square miles (1,383.1 km2), of which 533 square miles (1,380.5 km2) is land and 1 square mile (2.6 km2) (0.18%) is water.

Haywood County is situated on the southeastern edge of the New Madrid Seismic Zone, an area with a high earthquake risk.

Adjacent counties

National protected area


As of the census[4] of 2000, there were 19,797 people, 7,558 households, and 5,419 families residing in the county. The population density was 37 people per square mile (14/km²). There were 8,086 housing units at an average density of 15 per square mile (6/km²). The racial makeup of the county was 46.73% White, 51.05% Black or African American, 0.12% Native American, 0.09% Asian, 0.05% Pacific Islander, 1.38% from other races, and 0.58% from two or more races. 2.65% of the population were Hispanic or Latino of any race. Haywood County is the only county in Tennessee with a Black majority. There were 7,558 households out of which 33.40% had children under the age of 18 living with them, 45.80% were married couples living together, 22.00% had a female householder with no husband present, and 28.30% were non-families. 25.40% of all households were made up of individuals and 11.10% had someone living alone who was 65 years of age or older. The average household size was 2.59 and the average family size was 3.09.

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