Hemingford, Nebraska

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Hemingford is a village in Box Butte County, Nebraska, United States. The population was 993 at the 2000 census.



Hemingford is located at 42°19′12″N 103°4′25″W / 42.32°N 103.07361°W / 42.32; -103.07361 (42.320048, -103.073475)[3].

According to the United States Census Bureau, the village has a total area of 0.6 square miles (1.7 km²), all of it land.


As of the census[1] of 2000, there were 993 people, 373 households, and 258 families residing in the village. The population density was 1,530.4 people per square mile (589.8/km²). There were 438 housing units at an average density of 675.1/sq mi (260.2/km²). The racial makeup of the village was 93.15% White, 1.01% Native American, 3.32% from other races, and 2.52% from two or more races. Hispanic or Latino of any race were 6.85% of the population.

There were 373 households out of which 38.9% had children under the age of 18 living with them, 56.3% were married couples living together, 9.9% had a female householder with no husband present, and 30.6% were non-families. 28.4% of all households were made up of individuals and 15.0% had someone living alone who was 65 years of age or older. The average household size was 2.58 and the average family size was 3.18.

In the village the population was spread out with 30.5% under the age of 18, 7.0% from 18 to 24, 25.9% from 25 to 44, 20.6% from 45 to 64, and 15.9% who were 65 years of age or older. The median age was 38 years. For every 100 females there were 97.0 males. For every 100 females age 18 and over, there were 90.1 males.

The median income for a household in the village was $35,982, and the median income for a family was $44,167. Males had a median income of $32,159 versus $20,500 for females. The per capita income for the village was $14,944. About 8.8% of families and 10.2% of the population were below the poverty line, including 10.9% of those under age 18 and 16.4% of those age 65 or over.


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