Hilbert, Wisconsin

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Hilbert is a village in Calumet County in the U.S. state of Wisconsin. The population was 1,089 at the 2000 census.

Contents

Geography

Hilbert is located at 44°8′24″N 88°9′44″W / 44.14°N 88.16222°W / 44.14; -88.16222 (44.140040, -88.162250)[3].

According to the United States Census Bureau, the village has a total area of 1.1 square miles (2.9 km²), all of it land.

Demographics

As of the census[2] of 2000, there were 1,089 people, 430 households, and 288 families residing in the village. The population density was 982.8 people per square mile (378.8/km²). There were 458 housing units at an average density of 413.4/sq mi (159.3/km²). The racial makeup of the village was 98.26% White, 0.09% Native American, 0.73% Asian, 0.73% from other races, and 0.18% from two or more races. Hispanic or Latino of any race were 1.47% of the population.

There were 430 households out of which 33.3% had children under the age of 18 living with them, 54.4% were married couples living together, 6.5% had a female householder with no husband present, and 33.0% were non-families. 28.8% of all households were made up of individuals and 14.7% had someone living alone who was 65 years of age or older. The average household size was 2.53 and the average family size was 3.14.

In the village the population was spread out with 27.2% under the age of 18, 8.8% from 18 to 24, 27.9% from 25 to 44, 22.8% from 45 to 64, and 13.3% who were 65 years of age or older. The median age was 36 years. For every 100 females there were 98.7 males. For every 100 females age 18 and over, there were 94.8 males.

The median income for a household in the village was $42,938, and the median income for a family was $51,591. Males had a median income of $35,357 versus $22,826 for females. The per capita income for the village was $18,872. About 1.0% of families and 3.7% of the population were below the poverty line, including 3.1% of those under age 18 and 10.1% of those age 65 or over.

Notable residents

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