Horseshoe Lake, Arkansas

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Horseshoe Lake is a town in Crittenden County, Arkansas, United States. The population was 321 at the 2000 census.

The town is named after Horseshoe Lake, a horseshoe-shaped lake at the eastern tip of which the town is located.



Horseshoe Lake is located at 34°54′46″N 90°18′27″W / 34.91278°N 90.3075°W / 34.91278; -90.3075 (34.912702, -90.307523)[1].

According to the United States Census Bureau, the town has a total area of 0.4 km² (0.1 mi²), all land.

The elevation above sea level of Horseshoe Lake is 203 ft (61.9 m).[2]

The Horseshoe Lake

The town of Horseshoe Lake is situate will in the Mississippi River flood plains at the eastern tip of a U-shaped water body named Horseshoe Lake, which the town is named after.

Changes in the course of the Mississippi River resulted in the shape of the lake. The Horseshoe Lake is a former meander in the Mississippi River that was cut off, shortening the river, and is no longer connected to the river.

Horseshoe shaped lakes or oxbow lakes are not unusual in the flat plains of the lower Mississippi River and deltas of other rivers.


As of the census[3] of 2000, there were 321 people, 156 households, and 89 families residing in the town. The population density was 885.3/km² (2,264.4/mi²). There were 241 housing units at an average density of 664.6/km² (1,700.1/mi²). The racial makeup of the town was 94.39% White, 5.30% Black or African American, 0.31% from other races. 0.31% of the population were Hispanic or Latino of any race.

There were 156 households out of which 18.6% had children under the age of 18 living with them, 47.4% were married couples living together, 4.5% had a female householder with no husband present, and 42.9% were non-families. 35.9% of all households were made up of individuals and 16.7% had someone living alone who was 65 years of age or older. The average household size was 2.06 and the average family size was 2.65.

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