Hudson, Indiana

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Hudson is a town in Salem and Steuben townships, Steuben County, Indiana, United States. The population was 596 at the 2000 census.



Hudson is located at 41°31′57″N 85°4′54″W / 41.5325°N 85.08167°W / 41.5325; -85.08167 (41.532524, -85.081713)[3].

According to the United States Census Bureau, the town has a total area of 0.8 square miles (2.1 km²), all of it land.


As of the census[1] of 2000, there were 596 people, 212 households, and 154 families residing in the town. The population density was 728.1 people per square mile (280.6/km²). There were 238 housing units at an average density of 290.7/sq mi (112.1/km²). The racial makeup of the town was 97.32% White, 1.17% Native American, 0.17% Asian, 1.01% from other races, and 0.34% from two or more races. Hispanic or Latino of any race were 1.17% of the population.

There were 212 households out of which 40.1% had children under the age of 18 living with them, 61.3% were married couples living together, 6.1% had a female householder with no husband present, and 26.9% were non-families. 21.7% of all households were made up of individuals and 3.8% had someone living alone who was 65 years of age or older. The average household size was 2.81 and the average family size was 3.27.

In the town the population was spread out with 32.4% under the age of 18, 7.9% from 18 to 24, 34.4% from 25 to 44, 18.1% from 45 to 64, and 7.2% who were 65 years of age or older. The median age was 30 years. For every 100 females there were 104.8 males. For every 100 females age 18 and over, there were 104.6 males.

The median income for a household in the town was $42,321, and the median income for a family was $44,792. Males had a median income of $30,000 versus $24,954 for females. The per capita income for the town was $17,282. About 3.2% of families and 4.3% of the population were below the poverty line, including 2.4% of those under age 18 and none of those age 65 or over.


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