Humboldt, Nebraska

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Humboldt is a city in Richardson County, Nebraska, United States. The population was 941 at the 2000 census.



Humboldt is located at 40°9′54″N 95°56′45″W / 40.165°N 95.94583°W / 40.165; -95.94583 (40.165022, -95.945899)[3].

According to the United States Census Bureau, the city has a total area of 1.3 square miles (3.5 km²), all of it land.


As of the census[1] of 2000, there were 941 people, 427 households, and 239 families residing in the city. The population density was 703.5 people per square mile (271.1/km²). There were 508 housing units at an average density of 379.8/sq mi (146.4/km²). The racial makeup of the city was 96.17% White, 0.64% African American, 2.02% Native American, 0.11% Asian, 0.21% from other races, and 0.85% from two or more races. Hispanic or Latino of any race were 1.81% of the population.

There were 427 households out of which 23.0% had children under the age of 18 living with them, 44.7% were married couples living together, 7.5% had a female householder with no husband present, and 44.0% were non-families. 40.3% of all households were made up of individuals and 25.8% had someone living alone who was 65 years of age or older. The average household size was 2.10 and the average family size was 2.79.

In the city the population was spread out with 21.1% under the age of 18, 4.8% from 18 to 24, 20.2% from 25 to 44, 21.6% from 45 to 64, and 32.3% who were 65 years of age or older. The median age was 48 years. For every 100 females there were 86.3 males. For every 100 females age 18 and over, there were 83.7 males.

The median income for a household in the city was $27,672, and the median income for a family was $37,692. Males had a median income of $25,650 versus $20,909 for females. The per capita income for the city was $16,968. About 8.7% of families and 13.6% of the population were below the poverty line, including 23.1% of those under age 18 and 9.0% of those age 65 or over.

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