Hyde Park, Utah

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Hyde Park is a city in Cache County, Utah, United States. The population was 2,955 at the 2000 census. It is included in the Logan, Utah-Idaho Metropolitan Statistical Area.

Contents

History

Hyde Park was named for William Hyde, the first LDS branch president in the town. The first settlers were Latter-day Saints who moved from Lehi, Utah in 1860. Hyde served as branch president from 1860–1872 and then as bishop from 1872–1874, when he died.[3]

In 1930 the population of Hyde Park was 757.[4]

Geography

Hyde Park is located at 41°47′56″N 111°49′9″W / 41.79889°N 111.81917°W / 41.79889; -111.81917 (41.7988, -111.8191).[5] It lies in between the cities of North Logan and Smithfield, about 5 miles north of the county seat, Logan.

According to the United States Census Bureau, the city has a total area of 3.2 square miles (8.3 km²), all of it land.

Demographics

As of the census[2] of 2000, there were 2,955 people, 763 households, and 678 families residing in the city. The population density was 923.5 people per square mile (356.5/km²). There were 779 housing units at an average density of 243.4/sq mi (94.0/km²). The racial makeup of the city was 98.00% White, 0.14% African American, 0.07% Native American, 0.37% Asian, 0.10% Pacific Islander, 0.47% from other races, and 0.85% from two or more races. Hispanic or Latino of any race were 1.59% of the population.

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