Independence, Iowa

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Independence is a city in and the county seat of Buchanan County, Iowa, United States.[1] The population was 6,014 at the 2000 census. ==Geography== Independence is located at 42°28′13″N 91°53′38″W / 42.47028°N 91.89389°W / 42.47028; -91.89389 (42.470191, -91.893898)[2].

According to the United States Census Bureau, the city has a total area of 3.8 square miles (9.9 km²), of which, 3.7 square miles (9.6 km²) of it is land and 0.1 square miles (0.3 km²) of it (3.39%) is water.

Contents

Demographics

As of the census[3] of 2000, there were 6,014 people, 2,432 households, and 1,588 families residing in the city. The population density was 1,621.8 people per square mile (625.9/km²). There were 2,610 housing units at an average density of 703.9/sq mi (271.6/km²). The racial makeup of the city was 97.97% White, 0.28% African American, 0.05% Native American, 0.76% Asian, 0.22% from other races, and 0.71% from two or more races. Hispanic or Latino of any race were 0.50% of the population.

There were 2,432 households out of which 30.0% had children under the age of 18 living with them, 52.9% were married couples living together, 9.4% had a female householder with no husband present, and 34.7% were non-families. 30.3% of all households were made up of individuals and 16.0% had someone living alone who was 65 years of age or older. The average household size was 2.35 and the average family size was 2.93.

In the city the population was spread out with 25.4% under the age of 18, 7.3% from 18 to 24, 25.9% from 25 to 44, 22.5% from 45 to 64, and 18.9% who were 65 years of age or older. The median age was 39 years. For every 100 females there were 88.6 males. For every 100 females age 18 and over, there were 82.8 males.

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