Ireton, Iowa

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Ireton is a city in Sioux County, Iowa, United States. The population was 585 at the 2000 census.

Contents

Geography

Ireton is located at 42°58′27″N 96°19′4″W / 42.97417°N 96.31778°W / 42.97417; -96.31778 (42.974206, -96.317640)[1].

Indian Creek, a tributary of the Big Sioux River flows through the northern part of the city.[citation needed]

According to the United States Census Bureau, the city has a total area of 1.0 square miles (2.6 km²), all of it land.

Demographics

As of the census[2] of 2000, there were 585 people, 235 households, and 172 families residing in the city. The population density was 581.4 people per square mile (223.6/km²). There were 249 housing units at an average density of 247.5/sq mi (95.2/km²). The racial makeup of the city was 99.15% White, 0.17% Asian, and 0.68% from two or more races. Hispanic or Latino of any race were 0.34% of the population.

There were 235 households out of which 32.8% had children under the age of 18 living with them, 66.0% were married couples living together, 6.4% had a female householder with no husband present, and 26.4% were non-families. 25.1% of all households were made up of individuals and 14.5% had someone living alone who was 65 years of age or older. The average household size was 2.49 and the average family size was 2.97.

In the city the population was spread out with 25.3% under the age of 18, 8.5% from 18 to 24, 25.0% from 25 to 44, 20.7% from 45 to 64, and 20.5% who were 65 years of age or older. The median age was 39 years. For every 100 females there were 95.0 males. For every 100 females age 18 and over, there were 94.2 males.

The median income for a household in the city was $36,250, and the median income for a family was $44,063. Males had a median income of $30,673 versus $18,750 for females. The per capita income for the city was $16,879. About 1.7% of families and 1.0% of the population were below the poverty line, including none of those under age 18 and 4.8% of those age 65 or over.

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