Jacksonville, Ohio

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Jacksonville is a village in Athens County, Ohio, United States. The population was 544 at the 2000 census.



Jacksonville is located at 39°28′32″N 82°4′51″W / 39.47556°N 82.08083°W / 39.47556; -82.08083 (39.475693, -82.080865),[3] along Sunday Creek.[4]

According to the United States Census Bureau, the village has a total area of 0.3 square miles (0.7 km²), all of it land.


As of the census[2] of 2000, there were 544 people, 221 households, and 140 families residing in the village. The population density was 2,118.1 people per square mile (807.8/km²). There were 246 housing units at an average density of 957.8/sq mi (365.3/km²). The racial makeup of the village was 97.61% White, 0.37% Native American, and 2.02% from two or more races. Hispanic or Latino of any race were 0.55% of the population.

There were 221 households out of which 32.1% had children under the age of 18 living with them, 48.9% were married couples living together, 11.3% had a female householder with no husband present, and 36.2% were non-families. 31.7% of all households were made up of individuals and 15.4% had someone living alone who was 65 years of age or older. The average household size was 2.46 and the average family size was 3.09.

In the village the population was spread out with 26.5% under the age of 18, 7.2% from 18 to 24, 30.1% from 25 to 44, 21.7% from 45 to 64, and 14.5% who were 65 years of age or older. The median age was 37 years. For every 100 females there were 85.0 males. For every 100 females age 18 and over, there were 84.3 males.

The median income for a household in the village was $24,018, and the median income for a family was $30,556. Males had a median income of $26,500 versus $17,188 for females. The per capita income for the village was $13,900. About 20.1% of families and 24.5% of the population were below the poverty line, including 43.3% of those under age 18 and 5.2% of those age 65 or over.

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