Jonesboro, Indiana

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Jonesboro is a city in Grant County, Indiana, along the Mississinewa River opposite Gas City. The population was 1,792 at the 2006 census.



Jonesboro is located at 40°28′46″N 85°37′47″W / 40.47944°N 85.62972°W / 40.47944; -85.62972 (40.479340, -85.629847)[3].

According to the United States Census Bureau, the city has a total area of 0.9 square miles (2.2 km²), all of it land.


As of the census[1] of 2000, there were 1,887 people, 768 households, and 545 families residing in the city. The population density was 2,221.8 people per square mile (857.1/km²). There were 817 housing units at an average density of 961.9/sq mi (371.1/km²). The racial makeup of the city was 97.51% White, 0.16% African American, 0.26% Native American, 0.05% Asian, 1.01% from other races, and 1.01% from two or more races. Hispanic or Latino of any race were 1.75% of the population.

There were 768 households out of which 32.4% had children under the age of 18 living with them, 54.6% were married couples living together, 12.8% had a female householder with no husband present, and 29.0% were non-families. 25.0% of all households were made up of individuals and 8.2% had someone living alone who was 65 years of age or older. The average household size was 2.46 and the average family size was 2.91.

In the city the population was spread out with 25.4% under the age of 18, 7.6% from 18 to 24, 29.4% from 25 to 44, 24.3% from 45 to 64, and 13.3% who were 65 years of age or older. The median age was 37 years. For every 100 females there were 90.2 males. For every 100 females age 18 and over, there were 90.1 males.

The median income for a household in the city was $36,974, and the median income for a family was $42,036. Males had a median income of $33,611 versus $21,042 for females. The per capita income for the city was $16,723. About 4.1% of families and 6.5% of the population were below the poverty line, including 6.2% of those under age 18 and 5.6% of those age 65 or over.

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