Kewanee, Illinois

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Kewanee is a city in Henry County, Illinois, United States. "Kewanee" is the Winnebago word for prairie chicken[citation needed], which lekked there. The population was 12,944 at the 2000 census.

Contents

Geography

Kewanee is located at 41°14′28″N 89°55′32″W / 41.24111°N 89.92556°W / 41.24111; -89.92556 (41.241180, -89.925680).[1]

According to the United States Census Bureau, the city has a total area of 6.3 square miles (16.3 km²), of which, 6.3 square miles (16.3 km²) of it is land and 0.16% is water.

Demographics

As of the census[2] of 2000, there were 12,944 people, 5,353 households, and 3,377 families residing in the city. The population density was 2,062.1 people per square mile (795.8/km²). There were 5,879 housing units at an average density of 936.6/sq mi (361.4/km²). The racial makeup of the city was 90.27% White, 3.68% African American, 0.06% Native American, 0.35% Asian, 0.02% Pacific Islander, 3.69% from other races, and 1.95% from two or more races. Hispanic or Latino of any race were 6.10% of the population.

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